If the method is ParseInt(), check that the string is has an integer value and likewise for all other methods do the required checks. Then, check for unnecessary spaces and trim out all of them after that put several checks to verify that argument string matches the type of the method which we are using for parsing the string. To have a valid and well-formatted string, first of all, check whether the input string is not null. So, to avoid this exception, the input string provided has to be well formatted. The NumberFormatException is basically caused because the input string is not well formatted or illegal while parsing into a numerical value. If you provide the input string like "1.0" and you try to convert this string into an integer value, it will throw a NumberFormatException exception. There may be a mismatch between the input string and the type of the method which is being used for parsing.The maximum possible value of integer can be 127, but the value in the string is 135 which is out of range, so this will throw the exception. The input string may have an input which might exceed the range of the datatype storing the parsed string.The input string might be having a leading space.The input string might be having trailing space.The input string provided might be null.Since NumberFormatException occurs due to the inappropriate format of string for the corresponding argument of the method which is throwing the exception, there can be various ways of it. Output: Common reasons for NumberFormatException Using 'Integer.parseInt' is giving out of bound exception. I need to parse them to a 32-bit integer, such that, when the string value is above the integer capacity (231) it should return the nearest possible integer value. Int a = Integer.parseInt(null) //throws Exception as //the input string is of illegal format for parsing as it is null. I have a string of signed integer value that could range from '+2147483650' to '-9638527412'.
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